0=0.08t^2-1.6t+6

Solution for 0=0.08t^2-1.6t+6 equation:

0=0.08t^2-1.6t+6

We move all terms to the left:

0-(0.08t^2-1.6t+6)=0

We add all the numbers together, and all the variables

-(0.08t^2-1.6t+6)=0

We get rid of parentheses

-0.08t^2+1.6t-6=0

a = -0.08; b = 1.6; c = -6;
Δ = b2-4ac
Δ = 1.62-4·(-0.08)·(-6)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{0.64}}{2*-0.08}=\frac{-1.6-\sqrt{0.64}}{-0.16}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{0.64}}{2*-0.08}=\frac{-1.6+\sqrt{0.64}}{-0.16}
$